[最も選択された] if x 2xy-y^2=2 at the point (1 1) dy/dx is 824224-X 2 y 2 dx 2xy dy

Ex 5 3 6 Find Dy Dx In X3 X2y Xy2 Y3 81 Cbse

WebHInt 2x^2x(2y)y^22y2=0 As x is real, the discriminant must be \ge0 (2y)^28(y^22y2)\ge0\iff0\ge4(y2)^2\iff(y2)^2\le0 But as y is real, (y2)^2\ge0 The equation ofI treated the whole term first as a huge x

X 2 y 2 dx 2xy dy